log(a) b = 1/log(b) a
a ^ log(a) b = b
log(a) b^k = k log(a) b
a^m*a^n = a^(m+n)
1/log(2)3 = log(3) 2
1/log(4) 3 = log(3) 4 = log(3) 2^2
1/log(256) 3 = log(3) 256 = log(3) 2^8
⁹√( 3^(log(3) 2)*3^(log(3) 2^2)*3^(log(3) 2^3)**3^(log(3) 2^8)) =
= ⁹√(2*2^2*2^3*2^4*2^5*2^6*2^7*2^8) = ⁹√(2^(1+2+3+4+5+6+7+8) =
= ⁹√ 2^36 = ⁹√ (2^4)^9 = 2^4 = 16
