Объяснение:
1) Решение: 1/3=3^(-1), 1/9=3^(-2), тогда =-log(3) 27+1/2log(3) 27=-3+1/2*3=-1,5
2) (1/3)^(-2)=9, (1/9)^(-1)=9, значит log(1/3) 9=-2, log(1/9) 9=-1, тогда
5^(-2-(-1))=5^(-1)=1/5
loga xⁿ = n loga x
logaⁿ x = 1/n loga x
1) log1/3 27 - log1/9 27
log1/3 27 = log1/3 3³ = 3log1/3 3 = 3 * (-1) = -3
log1/9 27 = log3⁻² 3³ = 3/(-2) * log3 3 = -1.5
-3 - (-1.5) = -1.5
2) 5^log1/3 9-log1/9 9
log1/3 9 = log3⁻¹ 3² = 2/(-1) * log3 3 = -2
log1/9 9 = log9⁻¹ 9 = 1/(-1) * log9 9 = -1
5^(-2-(-1) = 5^(-1) = 1/5
