ОДЗ : x > 0

+ - +
__________₀__________₀__________
0 2
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1
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x ∈ (2 ; + ∞)

+ - +
_______________₀_____________₀_________
0 2
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_______________________₀_______________
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x ∈ (0 ; 1)
ответ : (0 ; 1) ∪ (2 , + ∞)