y=0
Объяснение:
(y+2)/(8y^3+1)-1/(4y+2)=(y+3)/(8y^2-4y+2)
(y+2)/(2y+1)(4y²+1-2y)-1/2(2y+1)-(y+3)/2(4y²+1-2y)=0
(2*(y+2)-(4y²+1-2y)-(y+3)(2y+1))/2(2y+1)(4y²+1-2y)=0
(2y+4-4y²-1+2y-2y²-3-7y)/2(2y+1)(4y²+1-2y)=0 y≠-1/2
-6y²-3y=0
y=0
6y+3=0
y=-1/2 не подходит по ОДЗ
Проверка
(0+2)/(8*0+1)-1/(4*0+2)=2-1/2=3/2
(0+3)/(8*0-4*0+2)=3/2
3/2=3/2
