ответ: y '( π/12 ) = 1 .
Объяснение:
y = sin( 2x + π/6 ) ; y '( π/12 ) - ?
y' = cos( 2x + π/6 ) * ( 2x + π/6 )' = 2cos( 2x + π/6 ) ; y' = 2cos( 2x + π/6 ) ;
y '( π/12 ) = 2cos( 2 * π/12 + π/6 ) = 2cosπ/3 = 2 * 1/2 = 1 .
