1)c3h6+hoh(н+) =c3h7oh-получение
2c3h7oh+2na=2c3h7ona+h2
ch3-ch2-ch2oh+cuo(t) =ch3-ch2-coh+cu+h2o
2)сh3-ch2-ch2-ch2oh + cuo(t) =ch3-ch2-ch2-coh +cu+h2o-получение
ch3-ch2-ch2-coh+h2=ch3-ch2-ch2-ch2oh
ch3-ch2-ch2-coh+ag2o(t) = ch3-ch2-ch2-cooh+2ag
3)2ch3-(ch2)3-cooh+2na=2ch3-(ch2)3-coona+h2
2ch3-(ch2)3-cooh+mgo=(ch3-ch2-ch2-ch2-coo)2mg+h2o
ch3-(ch2)3-cooh+naoh=ch3-(ch2)3-coona+h2o
2ch3-(ch2)3-cooh+na2co3=2ch3-(ch2)3-coona+co2+h2o
4)c2h5oh+ch3-cooh= c2h5-o-co-ch3+h2o
c5h11oh+h-cooh= c5h11-o-co-h +h2o
c7h13oh+c2h5-cooh= c7h13-o-co-c2h5+h2o
c5h11oh+ c5h11-cooh=c5h11-o-co-c5h11+ h2o
с - гипотенуза прямоугольного треугольника, с =37 см, S - его площадь, S=210 см², a и b - катеты.
S = (a*b)/2 = 210
По теореме Пифагора
c² = a² + b²
a² + b² = 37²
ab=420
a=420/b
( 420/b)² + b² = 1369
176400/b² + b² = 1369
b⁴ - 1369b² + 176400 = 0
b²=t > 0
t² - 1369t + 176400 = 0
D = 1369² - 4*176400 =1168561; √D = 1081
t₁ = (1369 + 1081)/2 = 1225; t₂ = (1369 - 1081)/2 = 144
b₁ = √1225 = 35; b₂ = √144= 12;
a₁ = 420/35 = 12; a₂ = 420/12 = 35
35 cм и 12 см
