![\sqrt[6]{4 + 3x - x ^{2} }](/tpl/images/4509/2899/7ae57.png)
![\displaystyle\bf \sqrt[6]{4+3x-x^2} \geq 0\\\\-x^2+3x+4\geq 0\\\\x^2-3x-4\leq 0 \\(x-4)(x+1)\leq 0](/tpl/images/2006/7124/63f74.png)
+ I - I + -1 ///////////// 4 ![\displaystyle\bf Otvet:x\in [-1 ; 4]](/tpl/images/2006/7124/30606.png)
![\sqrt[6]{4+3x-x^{2} }\\\\4+3x-x^{2} \geq0\\\\x^{2} -3x-4\leq0\\\\(x-4)(x+1)\leq0](/tpl/images/2006/7124/ec618.png)
+ + + + + [- 1]- - - - - [4]+ + + + +
////////////////
ответ : x ∈ [ - 1 ; 4]
