5x+2y=16
y=x−1
\left \{ {{y=x-1} \atop {5x+2(x-1)=16}} \right.{
5x+2(x−1)=16
y=x−1
\left \{ {{y=x-1} \atop {5x+2x-2=16}} \right.{
5x+2x−2=16
y=x−1
\left \{ {{y=x-1} \atop {7x=18}} \right.{
7x=18
y=x−1
\left \{ {{y=x-1} \atop {x=2 \frac{4}{7} }} \right.{
x=2
7
4
y=x−1
\left \{ {{y=2 \frac{4}{7} -1} \atop {x=2 \frac{4}{7} }} \right.{
x=2
7
4
y=2
7
4
−1
\left \{ {{y=1 \frac{4}{7}} \atop {x=2 \frac{4}{7} }} \right.{
x=2
7
4
y=1
7
4
ответ: (2 \frac{4}{7}; 1 \frac{4}{7})(2
7
4
;1
7
4
)
5х+2у=16
8х+3у=38|*3
15х-6у=48
16х+6у=76
