y=axⁿ; y'=a*n*xⁿ⁻¹
у=-8х + √х; √x=x^(1/2)
у'=-8*1*x¹⁻¹ + (1/2)*x^(1/2 - 1)= x⁰=1
-8 + (1/2)*x^(-1/2)=-8 + 1/(2*x^(1/2))= x^(-1/2)=1/(x^(1/2))
1/(2√x) - 8. Это ответ.
