X^2+5x(дробная черта) 1-6x + 41x^2-2x(дробная черта) 6x-1 , , в 0 ( полное решение без решебника! )

Solve for x over the real numbers:
-(x (x-5))/((6 x-1) (41 x^2-8 x+1)) = 0
Multiply both sides by -1:
(x (x-5))/((6 x-1) (41 x^2-8 x+1)) = 0
Multiply both sides by (6 x-1) (41 x^2-8 x+1):
x (x-5) = 0
Split into two equations:
x-5 = 0 or x = 0
Add 5 to both sides:
Answer: x = 5 or x = 0