Решите систему уравнений {(x+4)^2-(x+2)^2=2y+23 {(y+5)^2-(y+1^2=6x+15 - вопрос №173564742222235212615 от 16Milochka16 22.12.2021 02:44

Question

Алгебра: Решите систему уравнений {(x+4)^2-(x+2)^2=2y+23 {(y+5)^2-(y+1^2=6x+15

16Milochka16 · Answer

{(x+4)^2-(x+2)^2=2y+23 {x^2+8x+16-x^2-4x-4-2y-23=0 {4x-11-2y=0 I3
{(y+5)^2-(y+1^2=6x+15 {y^2+10y+25-y^2-2y-1-6x-15=0 {8y+9-6x=0 I2

{12x-33-6y=0
+
{-12x+18+16y=0
10y-15=0
10y=15
y=15/10
y=1,5
{y=1,5 {y=1,5 {y=1,5 {y=1,5
{8*1,5+9-6x=0 {12+9-6x=0 {-6x=-21 {x=3,5