Объяснение:
(4x²+7x)/(x-5)=(2x²-10)/(5-x)
(4x²+7x)/(x-5)- (2x²-10)/(5-x)=0
(4x²+7x)/(x-5)+ (2x²-10)/(x-5)=0
(4x²+7x+2x²-10)/(x-5)=0 ; x-5≠0== > x≠5
6x²+7x-10=0
Δ=49+240=289 ; √Δ=17
X1=(-7+17)/12=10/12=5/6
X2=(-7-17)/12=-24/12=-2
Proberka: x2=-2
L=[(4*(-2)²+7(-2)]/(-2-5)= ( 4*4-14)/-7=16-14/-7=-2/-7=2/7
P=[2*(-2)²-10]/(-2-5)=(2*4-10)/-7=(8-10)/-7=-2/-7=2/7
