1){x-5>0⇒x>5
{x-5<25⇒x<30
x∈(5;30)
2)x-7>0⇒x>7
2x+1>0⇒x>-1/2
x∈(7;∞)
log(2)(2x+1)-log(2)(x-7)²=3
log(2)[(2x+1)/(x-7)²=3
(2x+1)/(x-7)²=8
2x+1=8x²-112x+392
8x²-114x+391=0
D=12996-12512=484
x1=(114-22)/16=5,75
x2=(114+22)/16=8,5
Объяснение:
