Объяснение:
f(x)=(lnx+x^-1)·= (lnx)·+(x^-1)·=1/x-1/x^2
f(x0)=f(1)=1/1-1/1^2=1-1=0
k=0
произв.у= 1/(3х-2)·3 = 3/(3х -2)
произв.у(1) = 3/(3·1 -2) =3
k=3
