УПРОСТИТЬ Упростите: 2а + 5в) + (8а – 11в) + (9в - вопрос №1674104425811953106 от dashakeks2 09.03.2023 23:23

Question

Алгебра: УПРОСТИТЬ Упростите: 2а + 5в) + (8а – 11в) + (9в – 5а) (3х + 10у) – (6х + 3у) + (6у – 8х) (8с2 + 3с) + (-7с2 – 11с + 3) – (-3с2 – 4) (2р2 + 3рс + 8с2) – (6р2 – рс – 8с2) 10х2 – (7ах – 5х2 + 8а2) + (6ах – 4а2) (3а + 5в) + (9а – 7в) + (-5а + 16в) (2х – 11у) – (5х + 12у) + (3х – 17у) (3в2 + 2в) + (2в2 – 3в – 4) – (-в2 + 19) (8х2 + 2рх – 3р2) – (2х2 + 3рх – 3р2) 5ру – (4р2 + 3у2 – 7ру) – (12ру – 3у2)

dashakeks2 · Answer

1)=2а+5в+8а-11в+9в-5а=5а+3в2)=3x+10y-6x-3y+6y-8x=-11x+13y3)=8c2+3c-7c2-11c+3+3c2+4=4c2-8c+74)=2p2+3pc+8c2-6p2+pc+8c2=-4p2+4pc+16c25)=10x2-7ax+5x2-8a2+6ax-4a2=15x2-ax-12a26)=3a+5в+9а-7в-5а+16в=7а+14в7)=2x-11y-5x-12y+3x-17y=-40y8)=3в2+2в+2в2-3в-4+в2+19=6в2-в-159)=8x2+2px-3p2-2x2+3px-3p2=6x2+5px-6p210)=5py-4p2+3y2-7py-12py+3y2=-14py-4p2+6y2...