Объяснение:
3x²+13x-10=0
Δ=169+120=289
√Δ=17
x1=(-13-17)/6=-5
x2=(-13+17)/6=4/6=2/3
3x² + 13x - 10 = 0
a = 3, b = 13, c = -10
D = b² - 4 * a * c = 13² - 4 * 3 * (-10) = 289
√D = √289 = 17
x₁ = - 13 + 17 / 2 * 3 = 2/3
x₂ = - 13 - 17 / 2 * 3 = - 5
ответ: х₁ = 2/3, x₂ = -5
