2 sin2x – sinx = 0
sinx (2 sinx – 1) = 0
sinx = 0 2sinx – 1 = 0
x 1 = π/2 + πk, k Є R sinx = ½
x 2 = π/6 + 2 πk, k Є R
x 3 = 5π/6 + 2 πk, k Є R
Объяснение:
