(cosx+sinx)/(cosx-sinx)=ctgx
(cosx+sinx)/(cosx-sinx)=cosx/sinx
cosxsinx+sin^2x-cos^2x+sinxcosx=0
sin2x-cos2x=0
sin2x=cos2x
tg2x=1
x=П/8+Пk/2
ответ х=П/8+Пk/2
2sin^2x+√3*sin2x=1+2cosx
2sin^2x-sin^2x-cos^2x+√3*sin2x=2cosx
√3*sin2x-cos2x=2cosx
cosx+cos(П/3+2x)=0
cos(3x/2+П/6)=0 cos(П/6+x/2)=0
3x/2+П/6=П/2+Пk x/2+П/6=П/2+Пk
x=2П/9+2Пk/3 x=2П/3+2Пk
