1. Inroomumo tarpe42 + 50 -90(3/5 - ). /5(уз + V2)2 - вопрос №15947284142509035522 от Chinchil1a 23.10.2021 10:40

Question

Алгебра: 1. Inroomumo tarpe42 + 50 -90(3/5 - ). /5(уз + V2)2​

Chinchil1a · Answer

1 1
-- (cos6x + 4cos3x + 3) - -- (cos6x - 4cos3x + 3) =
8 8

1    1
= ( cos6x + 4cos3x + 3 - cos6x + 4cos3x - 3) = --- 8cos3x = cos3x
8    8

а сорь, там равно 1/2
Тогда, cos3x = 1/2
3x = +arccos1/2 + 2pk
3x = - arccos1/2 + 2pk

3x = pi/3 + 2pk
x1 = pi/9 + 2pk/3

x2 = -pi/9 + 2pk/3

1. Inroomumo tarpe42 + 50 -90(3/5 - ). /5(уз + V2)2​

1. Inroomumo tarpe
42 + 50 -90
(3/5 - ). /5
(уз + V2)
2