Основание равностороннего треугольника 8 дм, медиана основания 16 дм. Найдите оставшиеся медианы треугольника.

Выражение: 0.2*(5*y-3*x)+3*x
1. (2//10)*(5*y-3*x)+3*x
2. (1//5)*(5*y-3*x)+3*x
3. y-(3//5)*x+3*x
4. y+(12//5)*x
ответ: y+(12//5)*x
Выражение: -8*(7*p-9*q)+24*p
1. -(56*p-72*q)+24*p
2. -56*p+72*q+24*p
3. -32*p+72*q
ответ: -32*p+72*q
Выражение: 12*(6-4*x)+9*(7*x+3)
1. 72-48*x+9*(7*x+3)
2. 72-48*x+63*x+27
3. 72+15*x+27
4. 99+15*x
ответ: 99+15*x
Выражение: 4*(11*x-8)-5*(6-7*x)
1. 44*x-32-5*(6-7*x)
2. 44*x-32-(30-35*x)
3. 44*x-32-30+35*x
4. 44*x-62+35*x
5. 79*x-62
ответ: 79*x-62
Выражение: 7*x*(1-x)+13*x*(x-2)
1. (7-7*x)*x+13*x*(x-2)
2. 7*x-7*x^2+13*x^2-26*x
3. -19*x+6*x^2
ответ: -19*x+6*x^2
Выражение: 2*x^2*(5-3*x)-4*x*(x^2-17)
1. (10-6*x)*x^2-4*x*(x^2-17)
2. 10*x^2-6*x^3-4*x*(x^2-17)
3. 10*x^2-6*x^3-(4*x^2-68)*x
4. 10*x^2-6*x^3-(4*x^3-68*x)
5. 10*x^2-6*x^3-4*x^3+68*x
6. 10*x^2-10*x^3+68*x
ответ: 10*x^2-10*x^3+68*x

1) log₁₂3 + log₁₂4 = log₁₂(3*4) = log₁₂12 = 1
2) log₇98 - log₇2 = log₇(98/2) = log₇49 = 2
3) log₂5-log₂35 + log₂56 = log₂(5/35) + log₂56 = log₂(log₂8 = 3
4) log₁/₃5 - log₁/₃5 + log₁/₃ 9 = log₁/₃9 = -2

1) lg4 + lg250= lg(4*250) = lg1000 = 3
2) log₂6 - log₂ = log₂( = log₂32 = 5
3) (log₁₂4 + log₁₂36)² = (log₁₂144)² = 2² = 4
4) lg13 - lg 130 = lg = lg = -1
5) (log₂13-log₂52)⁵ = (log₂)⁵ = (log₂)⁵ = (-2)⁵ = -32
6) (log₀.₃9 - 2log₀.₃10)⁴ = (log₀.₃9 - log₀.₃100)⁴ = (log₀.₃)⁴ = (log₀.₃0.09)⁴ = 2⁴ = 16

1) log₃x = -1
x = 3⁻¹ = 1/3
2) log₂x = -5
x = 2⁻⁵ = 1/32
3) log₃x = 2
x = 3² = 9
4) log₄x = 3
x = 4³ = 64
5) log₄x = -3
x = 4⁻³ = 1/64
6) log₇x = 0
x = 7° = 1
7) log₁/₇x = 1
x = 1/7
8) log₁/₂x = -3
x = (1/2)⁻³ = 8

1) log₂log₂log₃81 = log₂log₂4 = log₂2 = 1
2) log₂log₃log₁/₃(1/27) = log₂log₃3 = log₂1 = 0
3) log₅125 = 3 = 2
4) log₄log₃81 = log₄4 = 1