решить тригонометрические уравнения! 1) cosx+1/2=0
2) 2sinx=√3
3) sin3x=-1
4) tgx+2=0
5) (ctgx+1)(tgx-1)=0

1)

x1 =2/3+2k

x2 =4/3+2k

2)

x1 =/3+2k

x2 =2/3+2k

3)

x1 =/2+2k/3

4)

x = -arcos(2) + k

5)

x = /4+k/2

Объяснение:

1) cos(x)+1/2 =0

cos(x) = -1/2

x1 =2/3+2k

x2 =4/3+2k

2) 2sin(x)=

sin(x) =/2

x1 =/3+2k

x2 =2/3+2k

3) sin3x=-1

x1 =/2+2k/3

4)  tgx+2=0

tgx = -2

x /2+k

x = -arcos(2) + k

5) (ctgx+1)(tgx-1)=0

(ctgx+1)(tgx-1) = -2/tan(2x)

x = /4+k/2