A) 1 - a + 3a² + 4aº +(-a? – 3a%); 6) x – 2xy + 3xy + (4xy + 2xy - 3x);
B) (2az - 322) + (-az - 24) + (-5az);

Question

Алгебра: A) 1 - a + 3a² + 4aº +(-a? – 3a%); 6) x – 2xy + 3xy + (4xy + 2xy - 3x); B) (2az - 322) + (-az - 24) + (-5az);

Даяна303 · Answer

Ну и уравнение!!8:(1+8:(1-8:(1+4:(1-4:(1-8х =1993-1 8:(1+8:(1-8:(1+4:(1-4:(1-8х ) =19921+8:(1-8:(1+4:(1-4:(1-8х =1/2498:(1-8:(1+4:(1-4:(1-8х))) =1/249-249/2498:(8:(1-8:(1+4:(1-4:(1-8х))) =-248/2491-8:(1+4:(1-4:(1-8х)) =8 * (-249/248)1-8:(1+4:(1-4:(1-8х)) =-249/318:(1+4:(1-4:(1-8х)) =31/31+249/318:(1+4:(1-4:(1-8х)) =280/311+4:(1-4:(1-8х)) =8*(31/280)1+4:(1-4:(1-8х)) =31/354:(1-4:(1-8х)) =31/35-35/354:(1-4:(1-8х)) =-4/351-4:(1-8х) =4 * (-35/4)1-4:(1-8х) =-354:(1-8х) =1+354:(1-8х) =361-8х=1/98х=9/9-1/98х=8/9х=1/9...