(2x+3)*(4x^2-3x+7)) ' = 2*(4x^2-3x+7) + (2x+3)*(8x-3)=8x^2-6x+14+16x^2-6x+24x-9=24x^2+12x+5 ((x^2-2x)/(x+4x^3))'= ((2x-2)*(x+4x^3) - (x^2-2x)*(1+12x^2))/((x+4x^3)^2) = (2x^2+8x^4-2x-8x^3-x^2-12x^4+2x+24x^3)/((x+4x^3)^2) = (-4x^4+16x^3+x^2)/((x+4x^3)^2)= x^2(-4x^2+16x+1)/x^2(1+4x^2)^2 =
(-4x^2+16x+1)/(1+4x^2)^2
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