(x + 5)² ≤ 25 - x²
x² + 10x + 25 - 25 + x² ≤ 0
2x² + 10x ≤ 0
x² + 5x ≤ 0
x(x + 5) ≤ 0
+ - +
[- 5][0]
ответ : x ∈ [- 5 , 0]
(х+5)^2<=25-х^2
(x+5)^2<=(5-x)(5+x)
(5+x)×(x+5-(5-x))<=0
(5+x)×(x+5-5+x)<=0
(5+x)×(x+x)<=0
(5+x)×2x<=0
{5+x <=0
{2x>=0
x<= -5
x >= 0
x€[-5;0]
