|3x + 5| - |x - 4| ≤ 1
3x + 5 = 0 ⇒ x = - 1 2/3 x - 4 = 0 x = 4
1) x < - 1 2/3
- (3x + 5) + (x - 4) ≤ 1
- 3x - 5 + x - 4 ≤ 1
- 2x - 9 ≤ 1
-2x ≤ 10
x ≥ - 5
x ∈ [- 5 ; - 1 2/3)
2) - 1 2/3 ≤ x < 4
3x + 5 + x - 4 ≤ 1
4x + 1 ≤ 1
4x ≤ 0
x ≤ 0
x ∈ [- 1 2/3 ; 0]
3) x ≥ 4
3x + 5 - x + 4 ≤ 1
2x + 9 ≤ 1
2x ≤ - 8
x ≤ - 4 - неуд
ответ : x ∈ [- 5 ; 0]
Решение задания прилагаю
