(хᵃ)ᵇ=хᵃ*ᵇ; ⁿ√х=х^(1/n); xᵃ * хᵇ=хᵃ⁺ᵇ; 1/xⁿ=x⁻ⁿ
(2^(1/2) * 2^(1/3) : 2^(1/6))³=
2^(3/2) * 2^(3/3) * 2^(-3/6)=
2^(1,5 + 1 - 0,5)=2²=4 - это ответ.
![\Big(\dfrac{2^{\frac{1}{2} }\cdot 2^{\frac{1}{3} }}{\sqrt[6]{2}}\Big)^3=\Big(\dfrac{2^{\frac{5}{6} }}{2^{\frac{1}{6}}}\Big)^3=\Big(2^{\frac{5}{6}-\frac{1}{6}}\Big)^3=\Big(2^{\frac{4}{6}}\Big)^3=2^{\frac{4}{6}\cdot 3 }=2^{2}=4](/tpl/images/1358/7913/68335.png)
