ответ:x=2kп/5; k€Z
x=2kп; k€Z
Объяснение:cos2x= cos3x
cos2x- cos3x=0
-2sin(5x/2) (sin-x/2)=0
-2sin(5x/2)*(-sin(x/2))=0
sin(5x/2) sin(x/2)=0
sin(5x/2) (sin-x/2)=0
sin(5x/2)=0
(sin-x/2)=0
x=2kп/5; k€Z
