Решите неравенство log5(x+2)+log5(1-x) =log5((1-x)(x^2-8x-8)) - вопрос №126823525151288 от kinzya 06.02.2023 05:39

Question

Алгебра: Решите неравенство log5(x+2)+log5(1-x) =log5((1-x)(x^2-8x-8))

kinzya · Answer

log5 (x+2)*(1-x) =log5 ((1-x)(x^2-8x-8)) (x+2)(1-x) =(1-x)(x^2-8x -8) x+2 =x^2-8x-8 x^2-9X-10 =0 D= 81+40=121; sqrt (D)= 11 x1=(9-11)/2=-1 x2=(9+11)/2= 2 (x+1)*(x-2) =0 x Є (-∞ ; -1] U [2; + ∞)      ...

Решите неравенство log5(x+2)+log5(1-x)< =log5((1-x)(x^2-8x-8))