Решите систему! х+у=8 х^2+у^2=16+2ху ! )

x=8-y

(8-y)^2+y^2=16+2(8-y)y

64-16y+y^2+y^2=16+16y-2y^2

4y^2-32y+48=0

2y^2-16y+24=0

y^2-8y+12=0

D=b^2-4ac=64-48=16

sqrtD=4

x1=(8+4)/2=6

x2=2

ответ:6;2

x=8-y

(8-y)^2+у^2=16+2(8-y)у

y2-16y+64+y2-16+2y2-16y=0

x=8-y

4y2-32y+48=0

x=8-y

y2-8y+12=0

x=8-y

y=6 или y=2

x=8-y

  y=6

  x=2

или

  y=2

  x=6