1(2x-1)(4x2-2x+1)-4x(2x2-1)=5x-2
раскроем скобки
8x3-4x2+2x-4x2+2x-1-8x3+4x = 5x-2
-8x2+3x+1 = 0
8x2-3x-1 = 0
Вычислим дискриминант D
D = b2 - 4ac = ( – 3)2 – 4·8·( – 1) = 41
x1 = -b + √ D = 3 + √ 41 = 3 + √ 41
2a 2·8 16
x2 = -b – √ D = 3 – √ 41 = 3 – √ 41
2a 2·8 16
