Путин12356
27.02.2021 21:20

Функцією задано формулу y=0.2x-2 яка з точок належить графіку цієї функції
а)(10;0) б)(5;1) в)(-5;-4) г)(0;-4)​

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Ответ:
23LOLKEK
16.06.2022 01:58

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0,0(0 оценок)
Ответ:
aliko705
07.10.2020 15:08
а)Найдите координаты точкb пересечения графика линейного уравнения -3x+2y-6=0 с осями координат.
Для этого одну из координат приравниваем 0 ( при пересечении прямой оси х значение у = 0  и наоборот):
2y-6=0
2у = 6
у = 6/2 = 3         это точка пересечения оси у.
-3x-6=0
3х = -6
х = -6/3 = -2      это точка пересечения оси х.   

б) определите, принадлежит ли графику данного уравнения точка k(1/3;3.5).
Надо координаты этой точки подставить в уравнение:
-3x+2y-6=0
-3*(1/3) + 2*3,5 - 6 = -1 + 7 - 6 = 0.
Уравнение верно - точка принадлежит графику.
Слинейной функцией а)найдите координаты точке пересечения графика линейного уравнения -3x+2y-6=0 с о
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