Объяснение:
1) y=1/(3x+2)=(3x+2)⁻¹
y'=(1/(3x+2))'=((3x+2)⁻¹)'=(-(3x+2)⁻¹⁻¹)(3x+2)'=-(3x+2)⁻²·3=-3(3x+2)⁻²=-3/(3x+2)²
2) y=x³+ctg³√x
y'=(x³+ctg³√x)'=(x³)'+(ctg³√x)'=3x²+3ctg²√x·(ctg√x)'=3x²+3ctg²√x·(-1/(sin²√x))(√x)'=3x²-((3ctg²√x)/(sin²√x))(1/(2√x))=3x²-(3ctg²√x)/(2√xsin²√x)
