x∛x - 4∛x² + 4 = 0
(∛x²)² - 4∛x² + 4 = 0
∛x² = t
t² - 4t + 4 = 0
(t - 2)² = 0
∛x² = t= 2
x² = 8
x = +- √8 = +- 2√2
ответ +-2√2
![x\cdot \sqrt[3]{x}-4\sqrt[3]{x^2}+4=0\\\\\sqrt[3]{x^4}-4\sqrt[3]{x^2}+4=0\\\\\left ( \sqrt[3]{x^2}-2 \right )^2=0\\\\\sqrt[3]{x^2}=2\\\\x=\pm 2\sqrt{2}](/tpl/images/1048/2286/e1c8f.png)