7)=0+1+0=1
8)=6*1+4*0+4*3/4=6+3=9
7)1;
8)9;
Объяснение:
7) cos(3π/2)-sin(3π/2)+ctg(3π/2)=
=cos(π+π/2)-sin(π+π/2)+ctg(π+π/2)=
=-cos(π/2)+sin(π/2)+ctg(π/2)=
=-0+1+0=1
8)6cos(0)+4sin(2π)+4sin^2(2π/3)=
=6*1+4*0+4*(√(3)/2)^2=
=6+0+4*3/4=6+3=9
